Ans (xy1) (xy1) By using a 2 − b 2 = ( a − b) ( a b) The only thing which is different from this is you must have to arrange it into this form So below are the steps x 2 − ( y 2 2 y 1) ==>we take common x 2 − ( y 1) 2 ==> ( a 2 2 a b b 2) = ( a b) 2
Prove that x^-1/x^-1 y^-1 x^-1/x^-1-y^-1=2y^2/y^2-x^2-Here is another solution Case 2 x,y= 1 y (x1) => x^y y 1 >= xy wonderful, in case the exponent is between 0 and 1, the Bernoulli inequality is reversed, ie (1x)^r views around the world You can reuse this answer Creative Commons License
Prove that x^-1/x^-1 y^-1 x^-1/x^-1-y^-1=2y^2/y^2-x^2のギャラリー
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